Question

Factorize:2x³-5x²-19x+42​

Answer 1

Answer:

p(x)=2x³-5x²-19x+42

Factors of 42=±1,±2,±3,±7

p(-3)=2X(-27)-5X9-19X-3+42

=-54-45+57+42

=-99+99

=0

So,x+3 is a factor of 2x³-5x²-19x+42

2x³-5x²-19x+42=(x+3)(2x²-11x+14)

=(x+3)(2x²-4x-7x+14)

=(x+3)[2x(x-2)-7(x-2)]

=(x+3)(x-2)(2x-7)

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