Question

Factorize ; 2x³ - x² - 13x - 6

Answer 1

Answer:

Step-by-step explanation:

[2 x³-x²-13 x- 6 ]=0 when x=-2

so,( x+2) is one of its factor.

now divide 2 x³-x²-13 x-6 by (x+2)

          (2 x³-x²-13 x-6) ÷ (x+2)

       ans =(2 x²-5 x-3)

on solving (2 x²-5 x-3)

           (by splitting the middle term)

        =2 x²-6 x+x-3

         =2 x(x-3)+1(x-3)

          =(2 x+1) (x-3)

so, three roots are(x+2),(2 x+1),(x-3)