Question

Factorize : 2y^3 + y^2 – 2y -1​

Answer 1

Answer:y^2(2y+1)-1(2y+1)

(y^2-1)(2y+1)

Step-by-step explanation:

Answer 2

Answer:

y=1,-1,-1/2

Step-by-step explanation:

substitute integers and check for the equation to be zero

here y=1 makes the equation zero

so one factor is 1

then by synthetic division

2y^3+y^2-2y-1

by taking the coefficients

1 ) 2 1 -2 -1

0 2 3 1

=0

by taking 2, 3 & 1 as coefficients

the equation 2y^2+3y+1=0

by factorization we can get the other two factors

we get , 2y^2+y+2y+1=0

y(2y+1)+1(2y+1)=0

(y+1)(2y+1)=0

y=-1 ,-1/2

the three factors are y=1,-1,-1/2