Factorize 2y^3+y^2-2y-1
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ANSWER:
- Factorisation of the above expression is (2y+1)(y+1)(y-1)
GIVEN:
- P(x) = 2y³+y²-2y-1
TO FIND:
- Factorise the above expression.
SOLUTION:
= 2y³+y²-2y-1
= (2y³+y²)+(-2y-1)
= y²(2y+1)-1(2y+1)
= (2y+1)(y²-1)
= (2y+1)[(y)² -(1)²]
= (2y+1)(y+1)(y-1)
Factorisation of the above expression is (2y+1)(y+1)(y-1)
NOTE:
Some important formulas:
(a+b)² = a²+b²+2ab
(a-b)² = a²+b²-2ab
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
(a+b)² = (a-b)²+4ab
(a-b)² = (a+b)²-4ab
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