Question

FACTORIZE 2y^3+y^2-2y-1​

Answer 1

Answer:

2y³ + y² - 2y - 1

y²(2y +1) - 1(2y+ 1)

(2y+1) ( y² - 1)

Answer 2

Step-by-step explanation:

Given,

$2y {}^{3} + {y}^{2} - 2y - 1$

The value without any variable can be used as a factor for p(y)

$p(y) = 2 {y}^{3} + y {}^{2} - 2y - 1$

Putting the values

(y-1) as a factor of p(y)

=> y-1=0

=> y=0+1

=> y=1

By Trial Method

$p(1) = 2 {(1)}^{3} + (1){}^{2} - 2(1) - 1$

$p(1) = 2 + 1 - 2 - 1$

$p(1) = 0$

Conclusion,

(y-1) is a factor of the given equation.

By Remainder Theorem,

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