factorize 2y^3+y^2-2y-1 using factor theorem
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# if this is write answer than please mark as brainliest
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rajat5841:
i wanted it as error and trial method,long division and then the factor theorem.
this is one more method
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2y²+y²-2y-1
=y²(2y+1) -1(2y+1)
=(y²-1) (2y+1)
=(y²-1²) (2y+1)
=it is in the form of( a²-b²) =(a+b) (a-b)
=(y+1)(y-1)(2y+1)
=y²(2y+1) -1(2y+1)
=(y²-1) (2y+1)
=(y²-1²) (2y+1)
=it is in the form of( a²-b²) =(a+b) (a-b)
=(y+1)(y-1)(2y+1)
this is not what i want . i wanted the three step method
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