Question

Factorize

2y³ + 5y² + 4y + 1​

Answer 1

Answer:

Step-by-step explanation:

Solving for y in y4=5y2−4 as follows:

=>y4−5y2+4=0

=>y4−y2−4y2+4=0

=>y2(y2−1)−4(y2−1)=0

=>(y2−1)(y2−4)=0

Either, (y2−1)=0

=>y2=1

=>y2=(±1)2

Therefore, y=±1

Or, (y2−4)=0

=>y2=4

=>y2=(±2)2

Therefore, y=±2

Hence, y=±1 or ±2. Thus giving four unique values for  y