Question

factorize 3√2a^3+16√2b^3+c^3-12 abc do the solution with long division method​

Answer 1

Answer:

2√2a³ +16√2b³ + c³ - 12abc

=(√2a)³ + (√8b)³ + (c)³ - 3(√2)(√√8) (abc)

=(√2a)³ + √8b + c) (2a² +8b²+c²-4ab

√2a - √8bc)

=(√2a + 2√2b + c) (2a² +8b²+c²-4ab √2ac - 2√2bc)