Factorize (3 x - 5 y)² - 49 z²
ii) 16y²b - 81bx²
Answers
How to solve your problem
(3−5)2−492
(3x-5y)^{2}-49z^{2}(3x−5y)2−49z2
Simplify
1
Expand the square
(3−5)2−492
\left(3x-5y\right)^{2}-49z^{2}(3x−5y)2−49z2
(3−5)(3−5)−492
(3x-5y)(3x-5y)-49z^{2}(3x−5y)(3x−5y)−49z2
2
Distribute
(3−5)(3−5)−492
{\color{#c92786}{(3x-5y)(3x-5y)}}-49z^{2}(3x−5y)(3x−5y)−49z2
3(3−5)−5(3−5)−492
{\color{#c92786}{3x(3x-5y)-5y(3x-5y)}}-49z^{2}3x(3x−5y)−5y(3x−5y)−49z2
3
Distribute
3(3−5)−5(3−5)−492
{\color{#c92786}{3x(3x-5y)}}-5y(3x-5y)-49z^{2}3x(3x−5y)−5y(3x−5y)−49z2
92−15−5(3−5)−492
{\color{#c92786}{9x^{2}-15xy}}-5y(3x-5y)-49z^{2}9x2−15xy−5y(3x−5y)−49z2
4
Distribute
92−15−5(3−5)−492
9x^{2}-15xy{\color{#c92786}{-5y(3x-5y)}}-49z^{2}9x2−15xy−5y(3x−5y)−49z2
92−15−15+252−492
9x^{2}-15xy{\color{#c92786}{-15xy+25y^{2}}}-49z^{2}9x2−15xy−15xy+25y2−49z2
5
Combine like terms
92−15−15+252−492
9x^{2}{\color{#c92786}{-15xy}}{\color{#c92786}{-15xy}}+25y^{2}-49z^{2}9x2−15xy−15xy+25y2−49z2
92−30+252−492
9x^{2}{\color{#c92786}{-30xy}}+25y^{2}-49z^{2}9x2−30xy+25y2−49z2
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Solution
92−30+252−492
9x^{2}-30xy+25y^{2}-49z^{2}9x2−30xy+25y2−49z2
2.