Question

Factorize-

35y square + 13y - 12

Whoevers' answer will be quick and correct with full explanation, I will mark as the brainliest.

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{x=\frac{3}{7}\:and\:\frac{-4}{5}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies 35 {y}^{2} + 13y - 12 = 0 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: y =?$

• According to given quesrtion :

$\tt: \implies {35y}^{2} + 13y - 12 = 0 \\ \\\bold{As \: we \: know \: that} \\ \tt: \implies D = {b}^{2} - 4ac \\ \\ \tt: \implies D= {13}^{2} - 4 \times 35 \times - 12 \\ \\ \tt: \implies D = 169 - ( - 1680) \\ \\ \tt: \implies D = 169 + 1680 \\ \\ \tt: \implies D = 1849 \\ \\ \tt: \implies x= \frac{ - b \pm \sqrt{D} }{2a} \\ \\ \tt: \implies x = \frac{ - 13 \pm \sqrt{1849} }{2 \times 35 } \\ \\ \tt: \implies x = \frac{ - 13 \pm \sqrt{1849} }{70} \\\\ \tt:\implies x=\frac{-13+43}{70}\:and\:\frac{-13-43}{70} \\\\ \green{\tt \therefore Factors \: are \: x = \frac{3}{7} \:and\:\frac{-4}{5}}$

Answer 2

Answer:

$\underline{\bigstar\:\textbf{According to the Question :}}$

$:\implies\sf35y^{2} + 13y - 12 = 0 \\\\\texttt{Here, a = 35;\quad b = 13;\quad c = - 12}\\\\{\scriptsize\qquad\bf{\dag}\:\:\texttt{Using Discriminat Formula :}}\\\\:\implies\sf y = \dfrac{- b\pm\sqrt{{b}^2 - 4ac}}{2a}\\\\\\:\implies\sf y = \dfrac{ - 13 \pm \sqrt{{13}^{2} - (4 \times 35 \times - 12)}}{2 \times 35}\\\\\\:\implies\sf y = \dfrac{ - 13\pm \sqrt{169 - ( - 1680)}}{70}\\\\\\:\implies\sf y = \dfrac{ - 13\pm \sqrt{169 + 1680}}{70}\\\\\\:\implies\sf y = \dfrac{ - 13\pm \sqrt{1849}}{70}\\\\\\:\implies\sf y = \dfrac{ - 13 \pm43}{70}\\\\\\:\implies\sf y = \dfrac{ - 13 + 43}{70} \quad or \quad y = \dfrac{ - 13 - 43}{70}\\\\\\:\implies\sf y = \dfrac{30}{70} \quad or \quad y = \dfrac{ -56}{70}\\\\\\:\implies\underline{\boxed{\sf y = \dfrac{3}{7} \quad or \quad y = \dfrac{ -4}{5} }}$