Question

factorize: 36 - a^2 - b^2 - 2ab

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Answer 1

Answer:

hope it helps

upto this step this can be solved only

Answer 2

Answer:

36-a²-b²-2ab = 0

a²+b²+2ab = 36

a²+b²+2ab - 36 = 0

(a+b)² - 6² = 0 [using identity (a+b)² = a²+b²+2ab]

Now if take a+b as x and 6 as y

then it will become x²-y² = 0

which can be further factorised as (x+y)(x-y)

In the case of this question the answer would be

(a+b+6)(a+b-6) = 0

Hope it helps you.

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