Question

factorize: 36x^2-1/169

Answer 1

$<b>$


36x²-1/69


(a²-b²)=(a+b)(a-b)


Break into above form of Equation;


(6x)²-(1/13)²

(6x+1/13)(6x-1/13)

=====================°

(6x-1/13)(6x+1/13)



Thanks!!!

Answer 2

your ans

given:-

36x2-1/169

(6x)2-1/(13)2

this is forming an identity

a2-b2=(a+b)(a-b)

so


answer:-

(6x+1/13)(6x-1/13)