Question

factorize:3a^2-20a+17 ​

Answer 1

Given :-

$3a {}^{2} - 20a + 17 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$3a {}^{2} - 20a + 17 = 0 \\ \\ 3 {a}^{2} - 17a - 3a + 17 = 0 \\ \\ a(3a - 17) - 1(3a - 17) = 0 \\ \\ (3a - 17)(a - 1) = 0$

Now split it into possible cases

$(3a - 17) = 0 \\ \\ (a - 1) = 0$

Hence,

$a_1 = \frac{17}{3} \\ \\ a_2 = 1$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

Answer:

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