factorize 3y(x+3y)+3(x+3y)^2
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Answer:
3y(x+3y)+3(x+3y)^2
=3(x+3y)y+3(x+3y)(x+3y)
=(3x+9y)y+(3x+9y)(x+3y)
=(3x+9y)(y+x+3y)
=(3x+9y)(x+4y)
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2
3y(x+3y) + 3(x+3y)²
taking x + 3y common
(x + 3y) [3y +3(x + 3y) ]
(x + 3y) [3y +3x + 6y ]
(x + 3y) [3x + 9y ]
Hence Factorised
Hope It Helps !!!
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