factorize 3z³ +4z²-13z +6
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3z ^{2} - 4x {}^{2} - 12x + 16}
3z
2
−4x
2
−12x+16
{z^2(3z-4)-4(3z-4)}z
2
(3z−4)−4(3z−4)
(3z-4)(z^2-4)}(3z−4)(z
2
−4)
(3z-4)(z+2)(z-2) }
ans.(3z-4)(z+2)(z-2)
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Answer:
Ans. (3z-4)(z+2)(z-2)
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