Question

factorize
4(2a-3b)^2 + 8 (2a-3b)​

Answer 1

Step-by-step explanation:

$4 {(2a - 3b)}^{2} + 8(2a - 3b) \\ \\ = 4(4 {a}^{2} - 12ab + 9 {b}^{2} ) + 16a - 24b \\ \\ = 16 {a}^{2} - 48ab + 36 {b}^{2} + 16a - 24b$

hope it helps.......

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Answer 2

Answer:

4(2a-3b)^2 + 8(2a - 3b )

by using II identity , i.e.,

(a - b)^2 = a^2 - 2ab + b^2

= 4( 4a^2 - 2*2a*3b + 9b^2 ) + 8(2a - 3b )

= 16a^2 - 48ab + 36b^2 + 16a - 24b.