Factorize 4(2a+b)Square-(a-b)square
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Answer:
Step-by-step explanation:
we have ,
4(2a+b)^2 -(a-b)^2
= 4(4a^2+b^2+4ab) - (a^2+b^2 - 2ab)
= 16a^2 + 4b^2 + 16ab - a^2 - b^2 + 2ab
= 15a^2 + 3b^2 + 18ab
= 3(5a^2 + b^2 + 6ab)
= 3(5a^2 + 6ab + b^2)
= 3(5a^2 + 5ab + ab + b^2)
= 3{5a (a+b) + b(a+b)}
= 3 (5a+b) ( a+b)
*Brainliest plzz*
*Hope it helps*
suhassgowda:
Thanks for your answer
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