factorize - { 4(3)^1/2 x^2 } + { 5x } - { 2(3)^1/2 } using middle term expansion
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3
Solution:
4√3x²+5x-2√3
Splitting the middle term,we get
= 4√3x²+8x-3x-2√3
=4√3x²+8x-√3*√3x-2√3
= 4x(√3x+2)-√3(√3x+2)
=(√3x+2)(4x-√3)
Therefore,
4√3x²+5x-2√3 =(√3x+2)(4x-√3)
•••
4√3x²+5x-2√3
Splitting the middle term,we get
= 4√3x²+8x-3x-2√3
=4√3x²+8x-√3*√3x-2√3
= 4x(√3x+2)-√3(√3x+2)
=(√3x+2)(4x-√3)
Therefore,
4√3x²+5x-2√3 =(√3x+2)(4x-√3)
•••
EnuSolanki:
4x(√3x+2)-√3(√3x+2), How we get -√3 as common
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