Question

Factorize 4(p + q) – 6 (p + q)^2​

Answer 1

Question :- Factorise :- 4(p + q) – 6 (p + q)^2 ?

Solution :-

Factorising is the reverse of expanding brackets .

The first step of factorising an expression is to 'take out' any common factors which the terms have.

So,

→ 4(p + q) - 6(p + q)²

→ 4(p + q) - 6(p + q)(p+q)

taking (p + q) common we get,

→ (p+q){4 - 6(p + q)}

→ (p + q)(4 - 6p - 6q)

Now, taking 2 common ,

→ 2(p + q)(2 - 3p - 3q) (Ans.)

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

Answer 2

$\sf{Answer}$

Step-by-step-explanation :-

We have to factorize

4(p + q) – 6 (p + q)²

We know that (a + b)² = (a+b)(a+b)

So,

4(p+q) -6 (p+q)(p+q)

Take common (p+q)

(p+q) [ 4 -6(p+q)]

(p+q) [ 4 - 6p - 6q ]

Take common 2

(p+q) 2 (2-3p - 3q]

Rearrange the term

2(p+q)(2-3p-3q) is the answer

So, the factorized form is

2(p+q)(2-3p-3q)