Question

factorize (4-x)^2-2x

Answer 1

by expanding we will get , 16+x²-8x-2x

16+x²-10x=0

x²-8x-2x+16=0

x(.x-8)-2(x-8)=0

(x-2)(x-8)=0

I hope this will help u :)

Answer 2

(4-x)²-2x
⇒4²-2*4*x+x²-2x
⇒16-8x+x²-2x
⇒16-10x+x²
or
⇒x²-10x+16
⇒x²-8x-2x+16
⇒x(x-8)-2(x-8)
∴(-8)(x-2) is the answer