Factorize (4-x)^2-2x
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Answer:
16+x^2-8x-2x=0
x^2-10x+16=0
x^2-8x-2x+16=0
x(x-8)-2(x-8)=0
(x-8)(x-2)=0
x-8=0 or x-2=0
x=8 or x=2
Answered by
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Answer:
by expanding we get, 16+x^2-8x-2x
16+x^2-10x
x(x-8)-2(x-8)
(x-8)(x-2)
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