Math, asked by taanushkhandelwal1, 15 days ago

factorize 4(y^2-1)^2-15(y^2-1)-4

Answers

Answered by Anonymous
2

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BrainlyHelper

BrainlyHelper

05.03.2018

Math

Secondary School

Solve by Cross Multiplication method :x /a +y / b= a + b , x/ a² + y/b²= 2.

nikitasingh79

nikitasingh79

CROSS - MULTIPLICATION METHOD:

The general form of a pair of linear equations

a1x + b1y + c1 = 0 , & a2x + b2y + c2 = 0.

When a1 / a2 ≠ b1 / b2, the pair of linear equations will have a unique solution.

To solve this pair of equations for x and y using cross-multiplication, we’ll arrange the variables x and y and their coefficients a1, a2, b1 and b2, and the constants c1 and c2 as shown below

⇒ x = b1 c2 - b2 c1 / a1 b2 - a2 b1

⇒ y = c1 a2 - c2 a1 / a1 b2 - a2 b1

The above equation is generally written as :

x/ b1 c2 - b2 c1 = y/ c1 a2 - c2 a1 = 1/a1 b2 - a2 b1

SOLUTION is in the attachment also.

x /a +y / b= a + b , x/ a² + y/b²= 2.

a1= 1/a, b1= 1/b, c1= -(a+b)= -a-b

a2= 1/a² , b2= 1/b² , c= -2

x y 1

----------- = ----------------- = -------------

b1 c1 c1 a1 a1 b1

b2 c2 c2 a2 a2 b2

x y 1

----------------- = ------------------- = ---------

1/b - a-b -a-b 1/a 1/a 1/b

1/b² -2 -2 1/a² 1/a² 1/b²

x y 1

----------- = --------------- = -----------------

-2/b +(a+b)/b² -(a+b)/a² + 2/a 1/ab² -1/ba²

x b² a² y a² b²

--------- = -------- = ----------

a - b a - b a - b

x = a² and y = b²

Hence the value of x = a² & y = b²

Answered by cutebrainlystar
0

Step-by-step explanation:

Brainly.in

Search for an answer to any question...

BrainlyHelper

BrainlyHelper

05.03.2018

Math

Secondary School

Solve by Cross Multiplication method :x /a +y / b= a + b , x/ a² + y/b²= 2.

nikitasingh79

nikitasingh79

CROSS - MULTIPLICATION METHOD:

The general form of a pair of linear equations

a1x + b1y + c1 = 0 , & a2x + b2y + c2 = 0.

When a1 / a2 ≠ b1 / b2, the pair of linear equations will have a unique solution.

To solve this pair of equations for x and y using cross-multiplication, we’ll arrange the variables x and y and their coefficients a1, a2, b1 and b2, and the constants c1 and c2 as shown below

⇒ x = b1 c2 - b2 c1 / a1 b2 - a2 b1

⇒ y = c1 a2 - c2 a1 / a1 b2 - a2 b1

The above equation is generally written as :

x/ b1 c2 - b2 c1 = y/ c1 a2 - c2 a1 = 1/a1 b2 - a2 b

x /a +y / b= a + b , x/ a² + y/b²= 2.

a1= 1/a, b1= 1/b, c1= -(a+b)= -a-b

a2= 1/a² , b2= 1/b² , c= -2

x y 1

----------- = ----------------- = -------------

b1 c1 c1 a1 a1 b1

b2 c2 c2 a2 a2 b2

x y 1

----------------- = ------------------- = ---------

1/b - a-b -a-b 1/a 1/a 1/b

1/b² -2 -2 1/a² 1/a² 1/b²

x y 1

----------- = --------------- = -----------------

-2/b +(a+b)/b² -(a+b)/a² + 2/a 1/ab² -1/ba²

x b² a² y a² b²

--------- = -------- = ----------

a - b a - b a - b

x = a² and y = b²

Hence the value of x = a² & y = b²

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