factorize 47 th question
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Hello,
The polynomial is :-
It is a cubic polynomial.
Hence to solve it or factorize it we need to use the trial and error method.
P(x) = 4x³+20x²+33x+18
P(-1) = 4(-1)³+20(-1)²+33(-1)+18
= - 4+20-33+18 = - 37 + 38 =1
P(-2) = 4(-2)³+20(-2)²+33(-2)+18
= - 32 + 80 - 66 -+18
= - 98+98 =0
So p(-2) =0
By factor theorem we can say that
X+2 is a factor of p(x)
Now,
We will divided p(x) by (x+2)
See the division in the attachment :
So p(x) = (x+2)(4x²+12x+9)
Now we will do middle term splitting of the second product of p(x) that is (4x²+12x+9)
See the attachment for splitting...
After splitting we got
P(x) = (x+2)(2x+3)(2x+3)
This is the factorization of 47 th number
Hope this will be helping you ✌️
The polynomial is :-
It is a cubic polynomial.
Hence to solve it or factorize it we need to use the trial and error method.
P(x) = 4x³+20x²+33x+18
P(-1) = 4(-1)³+20(-1)²+33(-1)+18
= - 4+20-33+18 = - 37 + 38 =1
P(-2) = 4(-2)³+20(-2)²+33(-2)+18
= - 32 + 80 - 66 -+18
= - 98+98 =0
So p(-2) =0
By factor theorem we can say that
X+2 is a factor of p(x)
Now,
We will divided p(x) by (x+2)
See the division in the attachment :
So p(x) = (x+2)(4x²+12x+9)
Now we will do middle term splitting of the second product of p(x) that is (4x²+12x+9)
See the attachment for splitting...
After splitting we got
P(x) = (x+2)(2x+3)(2x+3)
This is the factorization of 47 th number
Hope this will be helping you ✌️
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Anonymous:
Great
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