Question

factorize 49(a-b)^2 -25c^2 plz it's my exam who will get the correct answer I will mark him as brainliest​

Answer 1

Answer:

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Step-by-step explanation:

STEP  1 :

Equation at the end of step 1

(49 • ((a - b)2)) - 25 • (a + b)2

STEP  2 :

Equation at the end of step 2

49 • (a - b)2 - 25 • (a + b)2

STEP  3 :

3.1 Evaluate : (a-b)2 = a2-2ab+b2

3.2 Evaluate : (a+b)2 = a2+2ab+b2

STEP  4 :

Pulling out like terms

4.1 Pull out like factors :

24a2 - 148ab + 24b2 = 4 • (6a2 - 37ab + 6b2)

Trying to factor a multi variable polynomial :  

4.2 Factoring 6a2 - 37ab + 6b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (a - 6b)•(6a - b)

Final result :

4 • (a - 6b) • (6a - b)

Answer 2

Solution:

Since both terms are perfect squares, factor using the difference of squares formula,

a^2 - b^2 = (a + b)(a - b)

where

a = 7(a - b)

and

b = 5c

Therefore, the factor is

(7a - 7b + 5c) (7a - 7b - 5c)

Hope this will be helpful.