Question

factorize :-49x^2-42x+9​

Answer 1

Step-by-step explanation:

49x^2-42x+9=0

49x^2-21x-21x+9=0

7x(7x-3)-3(7x-3)=0

(7x-3)(7x-3)=0

x=3/7 , x=3/7

I HOPE THIS WILL HELP YOU

Answer 2

The factorized expression is $(7x-3)(7x-3)$

Therefore   $49x^2-42x+9=(7x-3)(7x-3)$

Step-by-step explanation:

Given expression is $49x^2-42x+9$

To factorize the given expression :

$49x^2-42x+9$

$=7^2x^2-2(7x)(3)+3^2$ ( it is of the form $a^2-2ab+b^2=(a-b)^2$ here a=7x and b=3 )

$=(7x-3)^2$ ( by using the property $(a-b)^2-(a-b)(a-b)$ here a=7x and b=3 )

$=(7x-3)(7x-3)$

Therefore  $49x^2-42x+9=(7x-3)(7x-3)$