Question

FACTORIZE...........
4a^2+12ab+9b^2-8a-12b
please answer fast and correct

Answer 1

( 2a )^2 + 12ab + (3b )^2 - 8a - 12b

= ( 2a + 3b )^ 2 - 4 ( 2a + 3b )

taking 2a + 3b as common --

{ 2a + 3b } [ 2a + 3b - 4 ] Ans.

Answer 2

Answer:

pls refer to the below

Step-by-step explanation:

Answer:

The factorization of the given expression is (2a+3b)(2a+3b-4)

Step-by-step explanation:

We have to factorize the expression 4a^2+12ab+9b^2-8a-12b4a2+12ab+9b2−8a−12b

Let us group the expressions as

(4a^2+12ab+9b^2)+(-8a-12b)(4a2+12ab+9b2)+(−8a−12b)

Now, we can write the first group as a perfect square and take GCF from second group.

\begin{gathered}((2a)^2+2\times2a\times3b+(3b)^2-4(2a+3b)\\=(2a+3b)^2-4(2a+3b)\\=(2a+3b)(2a+3b-4)\end{gathered}((2a)2+2×2a×3b+(3b)2−4(2a+3b)=(2a+3b)2−4(2a+3b)=(2a+3b)(2a+3b−4)

Thus, the factorization of the given expression is (2a+3b)(2a+3b-4)

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