factorize [(4a-b)^4-b^4]
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I hope it is correct
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candy10:
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ur answer is partially correct... u have to solve it further also but no problem thanks for the answer I've already solved it
oh thank you for the correction
that's fine
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nope u r wrong... how can u take 8 common when it's 2b square...
u ha e done this in the last step
yeah u are right it is 2
I took 2common from the first bracket,4 from the second and 2 from the last one
Sorry it should be 16 not 8
atleast u should have thanked me
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