Question

factorize 4a square - 9b square - 16c square +24 bc

Answer 1

Answer:

(2a-3b+4c)(2a+3b-4c)

Step-by-step explanation:

=4a²-9b²-16c²+24bc

=4a² - (9b²+16c²-24bc)

=(2a²)- [(3b)²+(4c)²-2(3b)(4c)]

=(2a)² - (3b-4c)²                     ∵ a²+b²-2ab = (a-b)²

=(2a- (3b-4c))  (2a+(3b-4c))    ∵ (a²-b²)=(a-b)(a+b)

=(2a-3b+4c)(2a+3b-4c)

Answer 2

Step-by-step explanation:

Hope it will help you .

Thanks .