Question

factorize 4a square +b square +c square -4ab +2bc -4ca using identity​

Answer 1

• Answer :-

→ 4a² + b² + c² - 4ab + 2bc - 4ca

→ (-2a)² + (b)² + (c)² - 2 × (-2a) × b + 2 × b × c - 2 × 2c × (-2a)

→ (- 2a + b + c)²

→ (-2a + b + c)(-2a + b + c)

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