Question

Factorize 4a²-9b²-16c²+24bc

Answer 1

Answer: (2a+3b–4c)(2a–3b+4c)

step by step instructions :

4a²–9b²–16c²+24bc

(2a)²–[(3b)²–2•3b•4c+(4c)²]

(2a)²–(3b–4c)². [a²–b² = (a+b)(a–b)]

(2a+3b–4c)(2a–3b+4c)

hope this helps !