factorize:4a⁴-7a²b²+3b⁴
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★ 4a⁴ - 7a²b² + 3b⁴
= (2a²)² - 7a²b² + (3b²)²
By using the identity
[ (a-b)² = a² - 2ab + b² ]
= ( 4a² - 3b² )²
= [ (4a - 3b) (4a + 3b)]²
Again identity [ a² - b² - ( a-b ) ( a+b) ]
= ( a² - b² ) ( 4a² - 3b² )
#BE BRAINLY ☺❣
★ 4a⁴ - 7a²b² + 3b⁴
= (2a²)² - 7a²b² + (3b²)²
By using the identity
[ (a-b)² = a² - 2ab + b² ]
= ( 4a² - 3b² )²
= [ (4a - 3b) (4a + 3b)]²
Again identity [ a² - b² - ( a-b ) ( a+b) ]
= ( a² - b² ) ( 4a² - 3b² )
#BE BRAINLY ☺❣
akhlaka:
Yup..!! Now it is correct
let me see
see at top
thanks sooooooo much
Welcome.. ☺
I hope my answer is correct
ehhhhhh
i also know your answer is correct
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