factorize : 4p^2 + 9q^2 + 16r^2 + 12pq – 24qr – 16rp
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let's see
_____________________________
we have,
4p²+9q²+16r²+12pq-24qr-16rp
= (2p)² + (3q)² + (4r)² + 2.2p.3q - 2.3q.4r - 2.4r.2p
[° • ° ( a +b -c )² = a²+b²+c²+2ab-2bc-2ac ]
that's why,
let
a=2p ,b=3q, c=4r
then,
the factor are
(2p+3q-4r)²
answer is (2p+3q-4r)(2p+3q-4r)
_____________________________
we have,
4p²+9q²+16r²+12pq-24qr-16rp
= (2p)² + (3q)² + (4r)² + 2.2p.3q - 2.3q.4r - 2.4r.2p
[° • ° ( a +b -c )² = a²+b²+c²+2ab-2bc-2ac ]
that's why,
let
a=2p ,b=3q, c=4r
then,
the factor are
(2p+3q-4r)²
answer is (2p+3q-4r)(2p+3q-4r)
taxo:
the first para is not clear
look , i factorized the polynomial into its components. like 4p² can be written as (2p)².
thanks
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