Question

factorize (4x^2-10x+4) and divide by (2x-1)​

Answer 1

Answer:

Let f(x) = 4x²-10x+4

g(x) =(2x-1)

We have to factorise,

f(x) /g(x).

Therefore,

$(4 {x}^{2} - 10x + 4) \div (2x - 1)$

2x-1 | 4x² - 10x +4 | 2x - 4

...... | - 4x²-2x |.....

_____________________

......... - 8x +4.........

............8x +4.........

______________________

............... ×××............

So we get that,

Quotient = 2x - 4

Remainder = 0

Hence the value is (2x-4).