Question

factorize 4x^2+9y^2+16^2+12xy-24yz-16xz

Answer 1

Hello dear friend .
here is Ur answer .
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$given \: \\ 4 {x}^{2} + 9 {y}^{2} + 16 {z}^{2} + 12xy - 24yz - 16xz \\ \\ sol. \\ = >( {2x)}^{2} + ( {3y)}^{2} + ( { - 4z)}^{2} + 2(2x)(3y) \\ + 2(3y)( - 4z) + 2( - 4z)(2x) \\ \\ using \: ide. = ( a + b + {c)}^{2} = \\ {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca \\ \\ = > 2x + 3y + ( - 4z )^{2} \\ = > (2x + 3y - 4z {)}^{2} \\ = > (2x + 3y - 4z)(2x + 3y - 4z) \\ answer$
Hope it's helps you.
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Answer 2

Hey!

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Question - 4x² + 9y² + 16z² + 12xy - 14yz - 16xz

Solution :-

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= (2x)² + (3y)² + (-4z)² + 2 × (2x) × (3y) + 2 × (3y) × (-4z) + 2 × (-4z) × (2x)

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= (2x)² + (3y)² + (-4z)²

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•Using this identity :-

=> (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

= (2x + 3y - 4z)²

= (2x + 3y - 4z) (2x + 3y -4z)

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Regards :)

Cybary

Be Brainly :)