Question

Factorize : 4x^2 + y^2 + z^2 + 4xy - 2yz - 4xz

Answer 1

4x²+y²+z²+4xy -2yz-4xz

=(-2x)²+(y)²+(z)² - 2(-2x)(y) -2(y)(z) +2(-2x)(z)

this is in the form of
(a-b-c)²=a²+b²+c²-2ab-2bc+2ac

here, a=-2,b=y,c=z

=[-2-y-z)²

Answer 2

Answer:

Here's the Answer :-

4x²+y²+z²+4xy -2yz-4xz

=(-2x)²+(y)²+(z)² - 2(-2x)(y) -2(y)(z) +2(-2x)(z)

this is in the form of

(a-b-c)²=a²+b²+c²-2ab-2bc+2ac

here, a=-2,b=y,c=z

=[-2-y-z)²