Question

factorize 4x^3+16x^2+19x+6 using factor theorem

Answer 1

Step-by-step explanation:

Equation at the end of step 1

(((4 • (x3)) + 24x2) + 19x) + 6 = 0

STEP

2

:

Equation at the end of step

2

:

((22x3 + 24x2) + 19x) + 6 = 0

STEP

3

:

Checking for a perfect cube

3.1 4x3+16x2+19x+6 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4x3+16x2+19x+6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 19x+6

Group 2: 4x3+16x2

Pull out from each group separately :

Group 1: (19x+6) • (1)

Group 2: (x+4) • (4x2)