Question

Factorize 4x²+12x+5​

Answer 1

Step-by-step explanation:

4x^2+12x+5=0

4x^2+10x+2x+5=0

2x(2x+5)+1(2x+5)=0

(2x+1)(2x+5)=0

2x+2=0 or 2x+5=0

x=(-2/2) or x=(-5/2)

x=(-1) or x=(-5/2)

Answer 2

QUESTION :-

Factorize :- $4x^2 + 12x + 5$

SOLUTION :-

By 'Splitting the Middle Term',

a * b = 20x^2  ; a + b = 12x

∴ a = +2x  ; b = +10x

$4x^2 + 12x + 5 = 4x^2 + 2x + 10x + 5\\\\\Rightarrow 2x\:(2x + 1) + 5\:(2x +1)\\\\= \bold {(2x + 1)(2x + 5)}$

*Substituting Each of the Factors, (2x + 1) and (2x + 5) to Zero, we get -

(2x + 1) = 0  ; (2x + 5) = 0

(a) $2x + 1 = 0\\\\\Rightarrow 2x = (-1)\\\\Therefore,\bold {x = \frac{-1}{2} }$

Similarly,

(b) $2x + 5 = 0\\\\\Rightarrow 2x = (-5)\\\\Therefore, \bold {x = \frac{-5}{2} }$

*(Just for an Additional Info. It's not a Part of the Question...)

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