Question

factorize 4x⁴y³-12x²y²-16x³y
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Answer 1

$Given \: 4x^{4}y^{3} - 12x^{2}y^{2}-16x^{3}y$

$= (4x^{2}y) \times (x^{2}y^{2}) - (4x^{2}y) \times (3y) - (4x^{2}y) \times (4x) \\= (4x^{2}y) (x^{2}y^{2}-3y-4x)$

Therefore.,

$\red{Factors \:of \: 4x^{4}y^{3} - 12x^{2}y^{2}-16x^{3}y}$

$\green { = (4x^{2}y) (x^{2}y^{2}-3y-4x)}$

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