Question

factorize 4xsq+ysq+zsq-4xy-2yz+4zx

Answer 1

=>4x²+y²+z²-4xy-2yz+4zx
=>(2x)²+(-y)²+(z)²+4x(-y)+2(-y)z+4zx
=>(2x-y+z)²

Hope it helps you.......

Answer 2

Hope u like my process
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$= > 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4zx \\ \\ = 2 {x}^{2} + 2 {y}^{2} - 4xy + 2 {z}^{2} + 2 {x}^{2} + 4zx - {y}^{2} - {z}^{2} - 2yz \\ \\ = 2( {x}^{2} + {y}^{2} - 2xy) + 2( {x}^{2} + {z}^{2} + 2xz) - 1( {y}^{2} + {z}^{2} + 2yz) \\ \\ = 2 {(x - y)}^{2} + 2 {(x + z)}^{2} - 1 {(y + z)}^{2} \\ \\ = 2(x - y)^{2} - (y + z) ^{2} + 2(z + x)^{2}$
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