Question

factorize : 4xy+8xy2
$4xy + 8xy { }^{2}$

Answer 1

$4xy + {8xy}^{2} \\ = 2 \times 2 \times x \times y + 2 \times 2 \times 2 \times \times y \times \\ take \: 2 \times 2 \times x \times y \: as \: common \: since \: they \: are \: present \: in \: both \: terms \\ then \: factorised \: expression = 4xy(1 + 2y)$
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