Factorize :- 4y^2-4y+1
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Given 4y^2 - 4y + 1
(2y - 1)(2y-1)
= (2y - 1)^2.
(or)
4y^2 - 4y + 1
= (4y^2 - 2y) + (-2y + 1)
= 2y(2y - 1) - (2y - 1)
= (2y - 1)(2y - 1)
= (2y - 1)^2.
(2y - 1)(2y-1)
= (2y - 1)^2.
(or)
4y^2 - 4y + 1
= (4y^2 - 2y) + (-2y + 1)
= 2y(2y - 1) - (2y - 1)
= (2y - 1)(2y - 1)
= (2y - 1)^2.
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