factorize 4y sq + 5 y + 1
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answer:
(4y+1)(y+1)
explanation:
4y^2+5y+1 can also be written as :
4y^2+ 4y + y + 1 --------> [5y = 4y + y]
then by grouping we get :
4y(y+1) + 1(y+1) -------> in 1(y+1) nothing except 1 is common, hence we take 1.
now we get :
(4y+1)(y+1)
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