Math, asked by yashchauhan06011, 11 months ago

factorize 4y2-4y+1 by middle term splitting

Answers

Answered by Anonymous
82

Step-by-step explanation:

 \bf \huge \underline{Question}

_____________________________

 \bf \huge \underline{solution}

 \bf \huge \underline{To\:Find}

 \sf\blue{\to\:4y^2-4y+1}

Splitting the middle term,

we get:-

 \sf\blue{\to\:= 4y^2 - 2y -2y +1}

 \sf\blue{\to\:= 2y(2y-1)-1(2y-1)}

 \sf\blue{\to\:= (2y-1)(2y-1)}

Therefore,

 \sf\blue{\to\:4y^2-4y+1 = (2y-1)(2y-1)}

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Answered by 20gunjanarora
4

Answer:

(2y-1)^2

Step-by-step explanation:

4y^{2} - 4y + 1 \\4y^{2} - 2y -2y + 1 \\2y(2y-1) -1(2y-1)\\(2y-1)(2y-1)\\(2y-1)^{2}

Hope it help you.

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