Question

factorize 4z³-4z²-11z+6​

Answer 1

Answer:

let f (z)=4z3-4z2=11z+6

put z=2 in f (z),we get

f (2)=4 (2)3-4 (2)2-11 (2)+6

=4(8)-4 (4)-22+6

=32-16-22+6=0

hence,(z-2) Is a factor of (z)

now let's divide f (z) with (z-2)

f (z)=(z-2)(4z2+4z-3)

=(z-2)(4z2+6z-2z-3)

=(z-2)[2z (z+3)-1 (2z+3)]

(z-2)(z+3)(2z-1)

hope it helps

tq....////

Step-by-step explanation:

Answer 2

Answer:

this is your answer I hope it helps you thank you have a nice day