Question

Factorize: (5^2−25+20)÷(−1)

Answer 1

(5p

2

−25p+20)÷5(p−4)

⇒5p

2

−25p+20=5(p

2

−5p+4)

=5[p

2

−4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p

2

−25p+20)÷(p−1)=

(p−1)

5(p−1)(p−4)

=5(p−4).

∴(5p

2

−25p+20)÷(p−1)=5(p−4).

Answer 2

Answer:

$= = = > ( {5}^{2} - 25 + 20) \div ( - 1) \\ = = = >( 25 - 25 + 20) \div ( - 1) \\ = = = > \: \: \: \: \: \: \: \: \: \: \: \: \: (0 + 20) \div ( - 1) \\ = = = > \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 20 \div ( - 1) \\ = = = > \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 20 \times \frac{1}{ - 1} \\ = = = > \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 20$

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