Question

factorize 50/y² - 2y²/ 81​

Answer 1

Answer:

2(5/y - y/9)(5/y + y/9)

Step-by-step explanation:

50y^2 - 2y^2/81

=2(25/y^2 - y^2/81)

=2[(5/y)^2 - (y/9)^2]       using identity:-    a^2 -b^2 = (a+b)(a-b)

=2(5/y - y/9)(5/y + y/9)   -ans

Answer 2

Step-by-step explanation:

$= \frac{50}{ {y}^{2} } - \frac{ {2y}^{2} }{81} \\ = 2( \frac{25}{ {y}^{2} } - \frac{ {y}^{2} }{81} ) \\ = 2 ( \frac{ {5}^{2} }{ {y}^{2} } - \frac{ {y}^{2} }{ {9}^{2} } ) \\ = 2 ({( \frac{5}{y}) }^{2} - ({ \frac{y}{9} }^{2} )) \\ = 2( \frac{5}{y} + \frac{y}{9} )( \frac{5}{y} - \frac{y}{9} )$

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