Question

Factorize: 54a6b+2a3b4​

Answer 1

Answer:

$\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \small\bold\red{factorize \: 54 {a}^{6} b + 2 {a}^{3} {b}^{4} } \\ \small\bold\red{ = 2 {a}^{3}( {27a}^{3} + {b}^{3}) } \\ \small\bold\red{ = 2 {a}^{3} ( {(3a)}^{3} + {(b)}^{3}) } \\ \small\bold\red{ = 2 {a}^{3}(3a + b)( {(3a)}^{2} - (3a) \times b + {b}^{2} )) } \\ \small\bold\red{= 2 {a}^{3}(3a + b)( {9a}^{2} - 3a b + {b}^{2} )}$

Identity used :-

${x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Answer 2

Step-by-step explanation:

this is correct ..........