Question

factorize
(5a-76b)3 + (19c-5a)3 +(7 b-9c)3​

Answer 1

Answer:

-207b+48c

Step-by-step explanation:

15a_228b+57c-15a+21b-9c

15a-15a-228b+21b +57c-9c

-207b+48c

Answer 2

Answer:

let A=5a-76b

B=19c-5a

C=7b-9c

Now A+B+C=(5a-76b) +(19c-5a)+(7b-9c) =0

since A+B+C=0 then A3+B3+C3=3ABC

=(5a-76b)3+(19c-5a) 3 +(7b-9c) 3=3 (5a-76b) (19c-5a) (7b-9c) ..