factorize:6-x-x^2.maths question anyone
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Answered by
1
Hi ,
6 - x - x²
= 6 - 3x + 2x - x²
= 3( 2 - x ) + x ( 2 - x )
= ( 2 - x ) ( 3 + x )
∴ Required factors are ( 2- x ) and ( 3 + x )
I hope this helps you.
: )
6 - x - x²
= 6 - 3x + 2x - x²
= 3( 2 - x ) + x ( 2 - x )
= ( 2 - x ) ( 3 + x )
∴ Required factors are ( 2- x ) and ( 3 + x )
I hope this helps you.
: )
Answered by
1
(6-x-x^2)
x^2-x-6 (multiply by minus)
x^2+3x-2x-6=0
x(x+3)-2(x+3)=0
(x-2)(x-3)=0
therefore, x=2 or x=-3
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