Math, asked by kulkarniambika08, 18 days ago

factorize 64a²+27 b³+144a²b+ 108ab²

Answers

Answered by chandan454380
0

Answer:

(4a+3b)³

Step-by-step explanation:

given 64a³+27 b³+144a²b+ 108ab²

we have to factorize the following equation we get

the gven equation can be written as

64a {}^{3}  +  {27b}^{3}  + 144 {a}^{2}b + 108a {b}^{2}  \\  =  {4a}^{3}  + 3 {b}^{3}  + 3 \times ( {4a)}^{2} \times 3b + 3 \times 4a \times ( {3b)}^{2}  \\  =  {(4a + 3b})^{3}

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